I've written a small program to practice getting user input using getchar() and outputting it using putchar() in C.
What I want my program to do: I want the program to ask the user to enter a char, store it in a char variable, and print it out. And then I want it to ask the user to enter another char, store it in another char variable, and print it out.
The following is my code:
#include <stdio.h>
int main()
{
printf("Please enter a char: ");
char myChar = getchar();
printf("The char entered is: ");
putchar(myChar);
printf("\n");
printf("Please enter another char: ");
char myChar2 = getchar();
printf("The char entered is: ");
putchar(myChar2);
printf("\n");
return 0;
}
When I run this program in my Terminal, the following is what I see, which is not how I expect it to behave.
cnewbie@cnewbies-MacBook-Pro c % ./a.out
Please enter a char: k
The char entered is: k
Please enter another char: The char entered is:
cnewbie@cnewbies-MacBook-Pro c %
When I run the program, it outputs "Please enter a char: " and waits for me to enter a char. I type k and hit return. Then it outputs not only "The car entered is: k" but also the other lines shown above all at once.
Question: Why doesn't my program wait for me to input another char?
I'm a beginner in C and I have no clue why this is behaving this way. Please help!!