C++ Load function from DLL into Boost function

Question

I want to load a particular function from DLL and store it inside the Boost function. Is this possible?

typedef void (*ProcFunc) (void);
typedef boost::function<void (void)> ProcFuncObj;
ACE_SHLIB_HANDLE file_handle = ACE_OS::dlopen("test.dll", 1);
ProcFunc func = (ProcFunc) ACE_OS::dlsym(file_handle, "func1");
ProcFuncObj fobj = func; //This compiles fine and executes fine
func(); //executes fine
fobj(); //but crashes when called

Thanks, Gokul.

I like how you used "executes fine" and "crashes" in the same sentence ;) — R. Martinho Fernandes, Aug 26 '11 at 11:49
Actually, i meant it crashes when called like fobj(), in the next sentence — Gokul, Aug 26 '11 at 11:49
@Moo-Juice : yup, i see that it is a valid function pointer. In fact it works fine, when called — Gokul, Aug 26 '11 at 11:51
Are you sure you don't need to specify the calling convention on ProcFunc? — Pete, Aug 26 '11 at 12:04
@Pete: I just edited to have a C-style cast. Other than that nothing else is there, if i use it as a C-style function pointer. can you clarify on what you mean by calling convention? — Gokul, Aug 26 '11 at 12:10

mloskot · Accepted Answer · 2011-08-26T13:34:26.220

You need to take care about names mangling and calling convention:

So, in your DLL:

// mydll.h
#pragma comment(linker, "/EXPORT:fnmydll=_fnmydll@4") 
extern "C" int WINAPI fnmydll(int value);

// mydll.cpp
#include "mydll.h"
extern "C" int WINAPI fnmydll(int value)
{
    return value;
}

Then, in your DLL client application:

#include <windows.h>
#include <boost/function.hpp>
#include <iostream>

int main()
{
    HMODULE dll = ::LoadLibrary(L"mydll.dll");
    typedef int (WINAPI *fnmydll)(int);

    // example using conventional function pointer
    fnmydll f1 = (fnmydll)::GetProcAddress(dll, "fnmydll");
    std::cout << "fnmydll says: " << f1(3) << std::endl;

    // example using Boost.Function
    boost::function<int (int)> f2 = (fnmydll)::GetProcAddress(dll, "fnmydll");
    std::cout << "fnmydll says: " << f2(7) << std::endl;
    return 0;
}

I'm sure this example builds and runs well.

C++ Load function from DLL into Boost function

1 Answers1