doctrine how to write WhereIn() with another sql query inside

Question

i have the folowing query in SQL

... where group_id IN (select group_id from alert where monitor_id = 4);

I want to write it in Doctrine but i don't know how to add the IN select into WHEREIN() clause ! any idea ?

this is what i did

$q = $this->createQuery('u') 
    ->select('u.email_address') 
    ->distinct(true)
    // ->from('sf_guard_user u') 
    ->innerJoin('u.sfGuardUserGroup ug') 
    ->where('ug.group_id IN(select group_id from alert where monitor_id=?',$monitor);     

$q->execute(); 

In the sfGuardUserTable.class:

public function getMailsByMonitor($monitor) {


        $q = Doctrine_Query::create()->from("alert a")->where("a.monitor_id", $monitor);
        $groups_raw = $q->execute(array(), Doctrine_Core::HYDRATE_ARRAY);
        $groups = array();
        print_r($groups_raw);
        foreach ($groups_raw as $gr) {
            $groups[] = $gr->id; //line 33
        }


        $q2 = $this->createQuery('u')
                ->select('u.email_address')
                ->distinct(true)
                ->innerJoin('u.sfGuardUserGroup ug')
                ->whereIn("ug.group_id", $groups);
        return $q2->execute();
    }

Answer 1

Usually you would do something like:

$q = Doctrine_Query::create()
  ->from('User u')
  ->whereIn('u.id', array(1, 2, 3));

But I think this one better fits your needs:

$q = Doctrine_Query::create()
  ->from('Foo f')
  ->where('f.group_id IN (SELECT f.group_id FROM Alert a WHERE a.monitor_id = ?)', 4);

Answer 2

One possible solution - fetch select group_id from alert where monitor_id = 4 into an array and use it in whereIn

$q = Doctrine_Query::create()->from("alert a")->where("a.monitor_id", 4);
$groups_raw = $q->execute(array(), Doctrine_Core::HYDRATE_ARRAY);
$groups = array();
foreach ($groups_raw as $gr){
    $groups[] = $gr->id;
}

$q2 = Doctrine_Query::create()->from("table t")->whereIn("t.group_id", $groups);

Two queries instead of one, but definitely do the trick.