Javascript remove the first line of a string just before the line break

Question

I have a variable that contains a string with lots of line breaks.

myvariable = '
1234556788,3434343434\n
1244556788,7234343834\n
1234556788,4434343434\n
1234556784,8434343434\n
1234556782,9444343434\n
';

I need some way of removing just the first one without leaving a blank first line if possible.

So that this:

1234556788,3434343434\n
1244556788,7234343834\n
1234556788,4434343434\n
1234556784,8434343434\n
1234556782,9444343434\n

turns into this:

1244556788,7234343834\n
1234556788,4434343434\n
1234556784,8434343434\n
1234556782,9444343434\n

So it would remove the first line after the \n

How can I do this?

one simple way is to convert to an array by splitting at newlines, remove the first element, then join again by newline character — Robin Zigmond, Apr 20 '22 at 12:58
You have a LEADING newline AND TWO newlines per line if your code looks like you posted - is that intended? — mplungjan, Apr 20 '22 at 13:07
Perhaps you mean `myvariable = myvariable.split(/\s+/).slice(2).join("\n")` https://jsfiddle.net/zmayf1hx/ — mplungjan, Apr 20 '22 at 13:11

score -1 · Answer 1 · edited Apr 20 '22 at 13:03

-1

myvariable = `1234556788,3434343434\n
1244556788,7234343834\n
1234556788,4434343434\n
1234556784,8434343434\n
1234556782,9444343434\n
`;
myvariable.substring(myvariable.indexOf('\n') + 2, myvariable.length);

edited Apr 20 '22 at 13:03

Ivar

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answered Apr 20 '22 at 13:02

user18879884

1

2

Note that template literals also preserve newlines, so `myvariable` now has two newlines every time. – Ivar Apr 20 '22 at 13:04

Javascript remove the first line of a string just before the line break

1 Answers1