0

Context: I'm trying to practice shelves in python and wanted to make the most basic program to try out methods.

I wrote this code:

#creates a shelf, with 3 set keys and 3 input values then prints it

import shelve

settings_shelf = shelve.open('TempData')

settings_shelf['volume'] = input()
settings_shelf['graphics'] = input()
settings_shelf['auto-save'] = input()

print(list(settings_shelf.keys())+ list(" ") + list(settings_shelf.values()))

settings_shelf.close()

Is there a better way to format this? instead of having 3 lines for inputs? I found this: Any way to use a tuple as key in a shelf? (Python) but I didn't really understand the answer..

I tried settings_shelf['volume','graphics'] = input(),input() but it throws out this error: even though it accepts the two inputs Traceback (most recent call last):

File "C:\Users\Simone\dev\Automate The Boring Stuff with Python\shelves.py", line 5, in settings_shelf['volume','graphics'] = input(),input() File "C:\Users\Simone\AppData\Local\Programs\Python\Python310\lib\shelve.py", line 125, in setitem self.dict[key.encode(self.keyencoding)] = f.getvalue() AttributeError: 'tuple' object has no attribute 'encode'

I tried adding print(tuple(xyz)) but still doesn't work.

Also.. would it be possible to write something like settings_shelf[input() = input() ? I tried this aswell but it messes up the end result it switches the last key and value

simone.benati
  • 99
  • 7

1 Answers1

0

From shelve docs:

The keys are ordinary strings.

So you need to convert tuple to string, and convert it back later if needed.

It't easier to use lists and json module

Here is the example:

import json
import shelve

settings_shelf = shelve.open('TempData')

obj = {
    'volume': 123,
    'graphics': 456,
    'auto-save': True,
}

folder, name = 'some', 'obj'

# Convert list to string
obj_key = json.dumps([folder, name])
print(obj_key)
# => '["some", "obj"]'

settings_shelf[obj_key] = obj

print(settings_shelf[obj_key])
# => {'volume': 123, 'graphics': 456, 'auto-save': True}

# Convert string back to objects
folder, name = json.loads(obj_key)
print(folder, name)
# => 'some obj'
Alex Kosh
  • 2,206
  • 2
  • 19
  • 18
  • Thank you @Alex , I was wondering would it be possible to accept input() for a key? So each time the program runs, you have to input the " settings " ? Instead of having them prefixed to those 3 strings ? – simone.benati Apr 13 '22 at 08:40
  • It's possible, but it's better to split logic into multiple lines, for first, get key names and value names, and only then assign them to `shelve`. Also don't forget to mark answer as acceptet if it helps you – Alex Kosh Apr 13 '22 at 09:48