Returning a buffer from c function

Question

I have this code:

#include <stdio.h>

int main() {

    
dosome();

}


char* dosome() {
    char* buffer = malloc(sizeof(char) * 128);    
    
    gets(buffer);

    puts(buffer);

    return buffer;
}

I want to return the buffer, so it can be printed, or worked with in the main function in some way. This gives a reutrn type error though I'm aware that gets() is not safe. This is a proof of concept

The error looks as follows simple.c:11:7: error: conflicting types for ‘dosome’ 11 | char* dosome() { | ^~~~~~

You need to declare a function before using it. So move `dosome` definition up before `main` or declare a prototype. — kaylum, Mar 31 '22 at 22:25

Primitive · Answer 1 · 2022-03-31T22:37:59.787

-3

You didn't declare the function

Add char * dosome(); Somewhere near the main function

edited Mar 31 '22 at 22:37

answered Mar 31 '22 at 22:27

Primitive

91
1
6

1

You don't "initialize" a function. – Aykhan Hagverdili Mar 31 '22 at 22:28
2

*You didn't initialize the function* - you mean "declared". Also "near" can be after as well. – Eugene Sh. Mar 31 '22 at 22:28
And what do you mean by the "empty buffer" reference? Why should `gets` need a buffer with anything in it? – kaylum Mar 31 '22 at 22:29
@kaylum He declared buffer in dosome(), and then used gets() on it as if there was a value in it already – Primitive Mar 31 '22 at 22:30
1

What? `gets` writes to the buffer. It doesn't care what is in the buffer to start with. – kaylum Mar 31 '22 at 22:37
@kaylum You're wrong and i'm right okay. In other words, i'll remove it from my post – Primitive Mar 31 '22 at 22:37

Returning a buffer from c function

1 Answers1