If Else statement not working as expected when passing arguments with spaces

Question

I have a simple if-else that takes a command-line argument and returns a value from a dictionary. When I enter 'Darth Vader', it returns 'Luke, I am your None' instead of 'No, I am your father'.

It works as expected with all other keys in the dictionary. Here is the code:

import sys

relations = {'Darth Vader': 'father', 'Leia': 'sister', 'Han': 'brother in law',
'R2D2': 'droid', 'Rey': 'Padawan', 'Tatooine': 'homeworld'}

key = sys.argv[1]

if key == 'Darth Vader':
  print("No, I am  your father")
else:
  print('Luke, I am your', relations.get(key))

This is probably because `Darth Vader` is two words. Try calling it with quotes around the argument — Patrick Haugh, Mar 24 '22 at 19:27

score 1 · Answer 1 · edited Mar 24 '22 at 19:31

1

key = sys.argv[1]

This gives you the second argument from the cmd (command line), but this leads to an error, since with the space between "Darth" and "Vader" makes "Darth" to be the only second argument.

edited Mar 24 '22 at 19:31

mkrieger1

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answered Mar 24 '22 at 19:31

FLAK-ZOSO

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It doesn't lead to an error, it just does something different than expected. – mkrieger1 Mar 24 '22 at 19:32

score 0 · Answer 2 · answered Mar 24 '22 at 19:31

0

As said Patrick Haugh, you should rename Darth Vader Darth_Vader, or use quotes ("Darth Vader") in your arguments instead of Darth Vader.

answered Mar 24 '22 at 19:31

Desktop Firework

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If Else statement not working as expected when passing arguments with spaces

2 Answers2