nslookup - return only the IP address of host

Question

I'd like to be able to return only the IP from a nslookup command. Currently if I execute:

>nslookup foo21.bar.local

it will return something like:

Server:     11.13.5.134
Address:    11.13.5.134#53

Name:   foo21.bar.local
Address: 11.13.35.312

I would like a command that returns just the:

11.13.35.312

Thanks for any answers.

score 2 · Accepted Answer · answered Mar 15 '22 at 13:55

2

dig has options to make that easy:

 dig +short foo21.bar.local

will just give you the A records, one per line (a domain can have more than one A record). To only get the first one:

 dig +short foo21.bar.local | head -n1

answered Mar 15 '22 at 13:55

Marcus Müller

thanks Marcus. That works. I guess dig is in all of our environments but not sure? I guess I was think of something using sed / grep /awk – Timothy Clotworthy Mar 15 '22 at 14:02

score 1 · Answer 2 · answered Mar 15 '22 at 14:00

1

Using dig as @Marcus suggest is the most clean way.

To answer your question, we can use awk to get only the line with Address and then get the second col:

nslookup google.com | awk '/^Address: / { print $2 }'

Will output:

216.58.208.110

answered Mar 15 '22 at 14:00

0stone0

2 Answers2