how print variable values in Go with fmt.Printl?

Question

I have the below code snippet:

x_variable := 12311
fmt.Println("message", "X variable has the value '+x_variable+' printed in the screen now")

How can I make that work? I've tried that in the Go playground but couldn't figure it out how to print the vaue properly.

What's wrong with `fmt.Println("abc", x, "xyz")`? It gives `abc 1234 xyz`. — aMike, Mar 10 '22 at 23:30

score 0 · Accepted Answer · answered Mar 10 '22 at 17:58

0

package main

import (
    "fmt"
)

func main() {
    x_variable := 12311
    fmt.Printf("message X variable has the value %d printed in the screen now", x_variable)
}

answered Mar 10 '22 at 17:58

Pratheesh M

1,028
6
13

score -2 · Answer 2 · answered Mar 10 '22 at 17:56

-2

What you need is Sprintf

You can find already an example there.

Since you want to print an integer, you can use the %d modifier.

Keep in mind that Sprintf family does not insert newline automatically, so you will also need \n

answered Mar 10 '22 at 17:56

gpopides

718
5
13

`Sprintf` doesn't print a value, it returns a value. – Adrian Mar 10 '22 at 18:12

how print variable values in Go with fmt.Printl?

2 Answers2