How to pass function to arq worker on python

Question

Run arq worker with some function that have some task to do but getting for below one. arq import Worker

w = Worker(functions=[],
    redis_settings=WorkerSettings.redis_settings(),
    max_jobs=1000,
    keep_result_forever=True,
    job_timeout=86000,
    max_tries=1000)
w.run()

Error on missing single function

Read the docs on [arq.worker.func](https://arq-docs.helpmanual.io/#arq.worker.func). — jarmod, Mar 01 '22 at 19:27

score 1 · Accepted Answer · answered Mar 14 '22 at 11:45

You need a function that the worker should run. Otherwise the worker would be quite unnecessary.

For example with the function the_tasks, you add it to the functions argument of the worker:

arq import Worker

async def the_task(ctx):
    print('running the task')
    return 42

w = Worker(functions=[the_task],
    redis_settings=WorkerSettings.redis_settings(),
    max_jobs=1000,
    keep_result_forever=True,
    job_timeout=86000,
    max_tries=1000)
w.run()

Maybe start with the demo example: https://arq-docs.helpmanual.io/#simple-usage

How to pass function to arq worker on python

1 Answers1