passing self with other argument on function call python

Question

I have my code below.

I want to call the "speak" function with two arguments inside the main() class. When I call speak it says that self its not defined

I'm new to POO.

class main():

    def blueon(self):
        print("teste")


    def speak(self,fala):
        self.blueon
        print(fala)

    speak("testeaaaaa")

score 1 · Answer 1 · 2022-03-01T12:21:57.457

Try something like this. Comments explain changes

class Main:      # Class name capitalized and no parenthesis if the class has no base classs
    def __init__(self):  # class constructor. Initialize here your variables
        pass

    # if you have a function that doesn't use self, you can declare it static
    @staticmethod          
    def blueon():     
        print("teste")

    def speak(self, fala):
        self.blueon()   # added missing parenthesis
        print(fala)

if __name__ == "__main__":  # add this so you can later import your class as a library without executing your test code
    m = Main()   # instantiate the class
    m.speak("testeaaaaa")   # call the speak method

score 0 · Accepted Answer · answered Mar 01 '22 at 12:16

You run speak() in wrong way.

First you have to create instance of class m = main() and later use m.speak("text").

And you have to do with different indetation.

BTW: There is good rule to use CamelCaseName for classes - class Main(): - it helps to recognize class in code, and it allows to do main = Main().
More in PEP 8 -- Style Guide for Python Code

# --- classes ---

class Main():

    def blueon(self):
        print("teste")

    def speak(self, fala):
        self.blueon()  # you forgot `()
        print(fala)

# --- main ---

main = Main()

main.speak("testeaaaaa")

passing self with other argument on function call python

2 Answers2