POST method of httplib python gives an error "socket.gaierror: [Errno -2] Name or service not known"

Question

The following code throws an error "socket.gaierror: [Errno -2] Name or service not known".

import httplib, urllib
attrs = urllib.urlencode({"username":"admin", "password":"admin"})
conn = httplib.HTTPSConnection("https://x.x.x.x:8181")
conn.request("POST", "/login", attrs)
response = conn.getresponse()
print response.status, response.reason

I don't want to use urllib2 module. Could anybody help me?... How to save the state of that server?, so that next time i directly post the values for the uri.

Yes, I can manually resolve the address. The above thing working fine with urllib2 module. But the need to use httplib. — ameet, Aug 19 '11 at 08:20

score 1 · Answer 1 · answered Aug 19 '11 at 08:18

1

I think you are not specifying the non-default port correctly: http://docs.python.org/release/2.6.7/library/httplib.html#httplib.HTTPSConnection

Try this instead:

   conn = httplib.HTTPSConnection("https://x.x.x.x",port=8181)

answered Aug 19 '11 at 08:18

Uku Loskit

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score 0 · Answer 2 · answered Jun 18 '12 at 01:57

0

I was getting a similar error with httplib.HTTPConnection, I found changing the url from "http://x.x.x.x" to "x.x.x.x" worked for me. Try removing the "http://" or "https://".

conn = httplib.HTTPSConnection("x.x.x.x:8181")

answered Jun 18 '12 at 01:57

Allan5

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score 0 · Answer 3 · edited Nov 08 '11 at 13:13

0

Try the following code:

conn = httplib.HTTPSConnection("x.x.x.x",port=8181)

edited Nov 08 '11 at 13:13

apaderno

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answered Nov 08 '11 at 11:57

Jolanda Verhoef

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POST method of httplib python gives an error "socket.gaierror: [Errno -2] Name or service not known"

3 Answers3