1

I used to have two filters to get data from my mongoDB, however I do not think that it is efficient considering it has to do two queries to the DB.


    filter = bson.M{
        "$and": []bson.M{
            {"partnerA.id": id},
            {"unlocked": false},
            {"deletedAt": nil},
        },
    }

    filter = bson.M{
        "$and": []bson.M{
            {"partnerB.id": id},
            {"unlocked": false},
            {"deletedAt": nil},
        },
    }

I tried to combine them using this solution I found and came out with this filter:

    filter := bson.M{
        "$and": []bson.M{
            {"partnerA.id": id},
            {"unlocked": false},
            {"deletedAt": nil},
        },
        "$or": bson.A{
            bson.M{"$and": []bson.M{
                {"partnerB.id": id},
                {"unlocked": false},
                {"deletedAt": nil},
            }},
        },
    }

However it does not work and I can't find the solution for it. Does anyone see the problem for this?

Thank you.

Marius
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1 Answers1

2

I presume you are trying to combine those two queries with OR operator. Another thing, I saw two similar clauses between the two, it's "unlocked": false and "deletedAt": nil.

You can have shorter query like below:

filter := bson.M{
    "$or": []bson.M{
        {"partnerA.id": id},
        {"partnerB.id": id},
    },
    "unlocked": false,
    "deletedAt": nil,
}

Update #1

How about a new query where I only return the values if ((partnerA.id = id and partnerA.unlocked = true) or (partnerB.id = id and partnerB.unlocked = true)) Blockquote

filter := bson.M{
    "$or": []bson.M{
        {
            "partnerA.id": id,
            "partnerA.unlocked": true,
        },
        {
            "partnerB.id": id,
            "partnerB.unlocked": true,
        },
    },
}
novalagung
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  • Thank you! This is exactly what I was looking for. It's working as it was supposed to now! – Marius Feb 19 '22 at 13:52
  • I have another question. How about a new query where I only return the values if ((partnerA.id = id and partnerA.unlocked = true) or (partnerB.id = id and partnerB.unlocked = true)) – Marius Feb 19 '22 at 13:58
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    @Marius please check my updated answer – novalagung Feb 19 '22 at 14:10