Create a program to print employee details using structures

Question

The code is not printing for name and salary of employee, also not asking for the salary of the employee, kindly mark the wrong items in the code.

#include<stdio.h>
#include<string.h>

struct employee{
    int code;
    char name[20];
    int salary;
};

void printEmployeeDetails(struct employee emp);

void printEmployeeDetails(struct employee emp){
    printf("Employee CODE is: %d\n" ,emp.code);
    printf("Employee NAME is: %s\n" ,emp.name);
    printf("Employee SALARy is: %d\n",emp.salary);     

}

int main(){
    struct employee e1;
    printf("Enter your CODE\n");
    scanf("%d",&e1.code);

    printf("Enter your NAME\n");
    scanf("%d",&e1.name);

    printf("Enter your SALARY\n");
    scanf("%d",&e1.salary);

    printEmployeeDetails(e1);

    //printf("The Employee Details Are: \n",printEmployeeDetails(e1));
    return 0;
}

Answer 1

I take that this is a C++ question. You might have turned off compiler warning when compile; as from the compiler warnings (I used onlinegdb compiler), there are a couple issues with your code

First

printf("Enter your NAME\n");
scanf("%d",&e1.name);

You are expecting e1.name to be a string here, so use "%s" instead of "%d"

Seconly, when using scanf for a char* variable, you only need to use scanf("%s", e1.name) (no need for the &)

For more details, read here: warning: format ‘%s’ expects type ‘char *’, but argument 2 has type ‘char (*)’

Final

printf("Enter your NAME\n");
scanf("%s",e1.name);