I made a calculator, but I can't figure out how to use try-except function properly, I've tried many solutions I found on the internet but none helps.
My calculator:
import math
print("Calculator")
number1 = input("Give a number:")
number2 = input("Give a number:")
while True:
print("(1) +")
print("(2) -")
print("(3) *")
print("(4) /")
print("(5)sin(number1/number2)")
print("(6)cos(number1/number2)")
print("(7)Change numbers")
print("(8)Quit")
print("Current numbers: ", number1, number2)
selection = (int(input("Please select something (1-6):")))
if selection == 1:
print("The result is:", number1 + number2)
if selection == 2:
print("The result is:", number1 - number2)
if selection == 3:
print("The result is:", number1 * number2)
if selection == 4:
print("The result is:", number1 / number2)
if selection == 5:
print("The result is:", math.sin(number1 / number2))
if selection == 6:
print("The result is:", math.cos(number1 / number2))
if selection == 7:
number1 = int(input("Give the first number:"))
number2 = int(input("Give the second number:"))
if selection == 8:
print("Thank you!")
break
I tried this both outside the while loop and inside:
number1 = input("Give a number:")
try:
number1 = int(number1)
except ValueError:
print("Invalid number.")
number2 = input("Give a number:")
try:
number2 = int(number2)
except ValueError:
print("Invalid number.")
If i don't put an int value it gives error "invalid number." but still continues with the code, when 2 inputs are given, nr or string doesnt mather it still continues like this ( end part ):
(7)Change numbers
(8)Quit
Current numbers: 24 d
Please select something (1-8)