Problem: responseModel being ignored. FastApi (python 3.8)

Question

I am using FastApi and My responseModel is being ignored. I am attempting to NOT return the password field in the response. Why does FastApi ignore my responsemodel definition?

Here is my api post method:

@app.post("/users")
def create_users(user: schemas.UserCreate, db: Session = Depends(get_db), response_model=schemas.UserOut):
    new_user = models.User(**user.dict())
    print(new_user)
    db.add(new_user)
    db.commit()
    db.refresh(new_user)
    return new_user

here is the postman return I should not see the password field:

{
    "password": "sdmfsladfj",
    "email": "hon99@gmail.com",
    "created_at": "2022-02-05T00:17:11.010020-06:00",
    "id": 10
}

Here is my responseModel definition in my schemas.py file:

class UserOut(BaseModel):
    id: int
    email: EmailStr
    created_at: datetime

    class Config:
        orm_mode = True




 anyio==3.5.0
    asgiref==3.5.0
    click==8.0.3
    dnspython==2.2.0
    email-validator==1.1.3
    emailvalidator==0.3
    fastapi==0.73.0
    greenlet==1.1.2
    h11==0.13.0
    idna==3.3
    psycopg2-binary==2.9.3
    pydantic==1.9.0
    sniffio==1.2.0
    SQLAlchemy==1.4.31
    sqlalchemy2-stubs==0.0.2a19
    sqlmodel==0.0.6
    starlette==0.17.1
    typing_extensions==4.0.1
    utcnow==0.3.0
    uvicorn==0.17.1

score 1 · Accepted Answer · answered Feb 05 '22 at 11:29

response_model is an argument to the view decorator (since it's metadata about the view itself), not to the view function (which takes arguments that are necessary for how to process the view):

@app.post("/users", response_model=schemas.UserOut):
async def ...

Problem: responseModel being ignored. FastApi (python 3.8)

1 Answers1