Calculating age in php using $date->diff returns wrong value

Question

I am calculating age of a person as follows-

$dob = new DateTime('01-03-2004', new DateTimeZone("Asia/Dhaka"));
$to = new DateTime("28-02-2022", new DateTimeZone("Asia/Dhaka"));
$interval = $dob->diff($to);

It returns 17 years 11 months 29 days.

But calculator.net shows 17 years 11 months 27 days.

Is there any other technique to calculate age in php?

https://3v4l.org/Dn6dV - 2 different versions of PHP and 2 different outputs — fkrzski, Jan 31 '22 at 07:17
Try it in UTC instead of Asia/Dhaka. See https://stackoverflow.com/a/24931746/17218429 — lukas.j, Jan 31 '22 at 07:24
Example code, converting dates to UTC before Difference calc. https://3v4l.org/VO24G — RiggsFolly, Jan 31 '22 at 10:19

score 0 · Answer 1 · answered Jan 31 '22 at 07:24

0

The difference is due to your time zone. Try using this:

$dob = new \DateTime('01-03-2004');
$to = new \DateTime("28-02-2022");
$interval = $dob->diff($to);

Without time zone specified, it will give you, your desired result.

Output:

DateInterval {#721 ▼
  interval: + 17y 11m 27d
  +"y": 17
  +"m": 11
  +"d": 27
  +"h": 0
  +"i": 0
  +"s": 0
  +"f": 0.0
  +"weekday": 0
  +"weekday_behavior": 0
  +"first_last_day_of": 0
  +"invert": 0
  +"days": 6573
  +"special_type": 0
  +"special_amount": 0
  +"have_weekday_relative": 0
  +"have_special_relative": 0
}

answered Jan 31 '22 at 07:24

Saud

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I am still not getting 27 days. – s.k.paul Jan 31 '22 at 07:41
@s.k.paul did you remove the time zone? – Saud Jan 31 '22 at 07:44
If you already removed the timezone from the object. There must be another instance or a global variable or property that is overriding the timezone in that object. You can use "UTC" as a parameter in the `DateTime()` object to override any predefined or default timezone. – Saud Jan 31 '22 at 08:01

Calculating age in php using $date->diff returns wrong value

1 Answers1