Regex pattern to check until next set of pattern but exclude it

Question

I'm trying to match and keep all the following text (including the numbers) until next set of numbers

string = "100 - Generic - Applicable (Prepaid leg) 101 - TFM - N/A 102 - TOPUP - Applicable (Prepaid leg) 103 - Staff - Applicable (Prepaid leg)"

my regex below grabs the next set of digits too and breaks the rest as you can see

\b(\d{3}.*?\s\d{3})

essentially the result should look like this

list = ['100 - Generic - Applicable (Prepaid leg)','101 - TFM - N/A','etc','etc']

I'm struggling to tell it to exclude\stop at the last pattern. I've looked at these, with out success obviously:

https://stackoverflow.com/questions/43899304/pcre-regex-matching-patterns-until-next-pattern-is-found

https://stackoverflow.com/questions/49487978/regex-to-match-pattern-until-next-occurence-of-it

https://stackoverflow.com/questions/33249035/regex-match-from-pattern-until-another-pattern

You need `\b(\d{3}.*?)(?=\s\d{3})` or `\b\d{3}.*?(?=\s\d{3})`. See [this thread](https://stackoverflow.com/q/12083308/3832970) where you can see how to also match till end if the right-hand context is missing. — Wiktor Stribiżew, Jan 26 '22 at 11:52

score 1 · Accepted Answer · answered Jan 26 '22 at 11:52

1

You can omit the capture group and use a positive lookahead instead.

\b\d{3}\b.*?(?=\s+\d{3}\b)

If you also want to include the last match, you can add an alternation to assert the end of the string.

\b\d{3}\b.*?(?=\s+\d{3}\b|$)

answered Jan 26 '22 at 11:52

The fourth bird

1 Answers1