Filtering another stream based on item in current stream using rxpy

Question

I want to find a match in another stream and combine it with current item.

numbers = [1, 2, 3, 4, 5]
numbers_in_char = ["2", "1", "3", "5", "4"]

textnumbers_in_stream = rx.defer(rx.from_iterable(numbers_in_char))


def exists_in_words(number, words):
    return words.pipe(
        op.filter(lambda w: int(w) == number),
        op.map(lambda w: (number, w))
    )


rx \
    .from_iterable(numbers) \
    .pipe(op.map(lambda number: exists_in_words(number, textnumbers_in_stream))) \
    .subscribe(lambda row: print(row))

I expect to have these printed:

(1,"1")
(2,"2")
(3,"3")
...

But I have:

None
None
None
...

Someone can give me an idea what i have done wrong?

many thanks in advance

Nuno Carvalho · Answer 1 · 2022-01-23T12:25:10.307

You are missing a return statement here:

def exists_in_words(number, words):
    return words.pipe(
        op.filter(lambda w: int(w) == number),
        op.map(lambda w: (number, w))
    )

If you change this to print the tuple:

rx.from_iterable(numbers) \
    .pipe(op.map(lambda number: exists_in_words(number, textnumbers_in_stream))) \
    .subscribe(lambda row: print(row[0], row[1]))

The output is:

<rx.core.observable.observable.Observable object at 0x7f559b1df898> <rx.core.observable.observable.Observable object at 0x7f559b1dfba8>
<rx.core.observable.observable.Observable object at 0x7f559b1dfba8> <rx.core.observable.observable.Observable object at 0x7f559b1df198>
<rx.core.observable.observable.Observable object at 0x7f559b1df198> <rx.core.observable.observable.Observable object at 0x7f559b1df240>
<rx.core.observable.observable.Observable object at 0x7f559b1df240> <rx.core.observable.observable.Observable object at 0x7f559b1df898>
<rx.core.observable.observable.Observable object at 0x7f559b1df898> <rx.core.observable.observable.Observable object at 0x7f559b1dfba8>

To solve that string representation take a look at this issue .

I add ```on_next```, ```on_error``` and ```on_completed``` to print an item in stream. But still it prints a tuple of number and Observable object. It seems ```exists_in_word(number, words)``` return a tuple of number and Observable not a tuple of number and number. — slawalata, Feb 17 '22 at 03:46

score 1 · Answer 2 · answered Feb 18 '22 at 03:51

from rx import operators as op
import rx


def exists_in_words(number, words):
    return words.pipe(
        op.filter(lambda w: int(w) == number),
        op.map(lambda w: (number, w))
    )


def my_on_next(item):
    print(f"####### {item}", flush=True)


def my_on_error(throwable):
    print(throwable)


def my_on_completed():
    print('Done')


numbers = [1, 2, 3, 4, 5]
numbers_in_char = ["1", "2", "3", "4", "5"]

text_as_numbers_in_stream = rx.from_iterable(numbers_in_char)


def print_tuple(x):
    print(f"{x[0]}:{x[1]}", flush=True)
    return x


rx \
    .from_iterable(numbers) \
    .pipe(op.flat_map(lambda number: exists_in_words(number, text_as_numbers_in_stream))) \
    .subscribe(lambda x: my_on_next(x), my_on_error, my_on_completed)

I find it.. I change defer to .from_iterable() for the second stream..

I filter an item from first stream based on second stream in by simply reverse the process :

def exists_in_words(number, words):
    return words.pipe(
        op.filter(lambda w: int(w) == number),
        op.map(lambda w: (number, w))
    )

later flatMap() filter result which is an Observable. I do it by feeling, done it many times in java reactor. Basically to remove its encloser (Observer object) and get its content...

and tadaaaaaa.. it works.

####### (1, '1')
####### (2, '2')
####### (3, '3')
####### (4, '4')
####### (5, '5')
Done

score 0 · Answer 3 · answered Jan 25 '22 at 17:54

0

If you want to combine two observable element wise, you can use the zip operator:

numbers = [1, 2, 3, 4, 5]
numbers_in_char = ["1", "2", "3", "4", "5"]


d = rx.from_iterable(numbers).pipe(
    ops.zip(rx.from_iterable(numbers_in_char)),
).subscribe(lambda row: print(row))

This returns the expected result:

(1, '1')
(2, '2')
(3, '3')
(4, '4')
(5, '5')

Note that the current release of RxPY (3.2) has a bug that prevents this example to work. You can test this with 3.1.1, or hopefully with the upcoming release.

answered Jan 25 '22 at 17:54

MainRo

136
1
3

Thanks for comment, but it didn't answer my original question.. zip combines 2 streams first element from one stream with first element another stream. My question is __to find or filter from a value in one stream (ie:1) if exists in another stream (in this case "1")__. – slawalata Feb 17 '22 at 03:52
ok, from your original example I thought it was an element-wise combination. Your solution is the way to go: You have to iterate on "numbers_in_char" for each item in "numbers". – MainRo Feb 18 '22 at 21:42

Filtering another stream based on item in current stream using rxpy

3 Answers3