Python, remove brackets from using values from a dict

Question

mappe = {10 : [10, 1]}
pair = list(mappe.values())
liste = []
liste.append((pair) + [5, 6])

--> [[10,1], 5, 6]]

how can i remove the inner brackets?

Your brackets are unbalanced. Furthermore, what is your desired result? Do you just want a list `liste = [10, 1, 5, 6]`? In that case, just write `liste = pair + [5,6]`. — eandklahn, Jan 18 '22 at 14:18
`liste = mappe[10] + [5, 6]` or `liste = list(mappe.values())[0] + [5, 6]` — rzlvmp, Jan 18 '22 at 14:20

score 1 · Answer 1 · answered Jan 18 '22 at 14:19

1

You can use liste.extend() instead. The function append adds the value that you pass in as a single element to a list, while extend will take an iterable object and put each item in the list as an item. Like this: liste.extend(pair + [5,6])

answered Jan 18 '22 at 14:19

Nathan Roberts

828
2
10

score 1 · Answer 2 · answered Jan 18 '22 at 14:23

Just another approach maybe? it might do , depends on your task if you could elaborate please I'll gladly help

mappe = {10 : [10, 1]}
#pair = list(mappe.values())
pair=[]
for element in mappe:
    for x in mappe[element]:
        pair.append(x)
    
liste = pair.copy()
liste+=[5, 6]

print(liste)

Python, remove brackets from using values from a dict

2 Answers2