Python: Get part of string between appropriate braces and symbols

Question

For if i have the following in a text file:

{
fun cake(){
"im cute"
subfun notcake(){
"dont close the question!"
}
}
fun notcute(){
"Did you just say..."
}
}

i want to get the stuff between two braces of the fun cake(). Those particular braces, and matching pairs with opening and closing braces so that i dont get the strings of other braces.

(the focused point is highlighted in bold)

You should use RegEx with the re library in python. Another aproach would be using the split method of an string , but this will only work if your structure is always the same. — Fran Arenas, Jan 17 '22 at 06:49
also with regex, get the one of only the brace of fun cake()?? — Xephonine, Jan 17 '22 at 07:08

HIMANSHU PANDEY · Accepted Answer · 2022-01-17T10:26:45.253

Here's a general purpose library function I've created for you

def makePairs(code: str, bracket_list = ['[', '{', '(', '<']) -> dict:
    """
    Pair Maker
    =========
        Finds and creates corresponding pairs of all types of brackets given in the 'bracket_list' present in the 'code'.

        Parameters
        ----------
        1. Code : str - given string of code
        2. Bracket List : list - all types of brackets whose pair has to be searched and mapped

        Returns
        -------
        A dictionary that maps an opening bracket position to corresponding closing bracket position

        Example
        -------
        >>> bracePairs = makePairs(code)\n
        >>> for open, close in bracePairs.items():\n
        >>>    print(code[open : close+1])
    """
    
    naivePairs = { '{':'}', '[':']', '(':')', '<':'>' }
    pairs:dict = {}                                                         # maps '{' position to corresponding '}' position
    openBraceStack = []                                                     # will store the consecutive brace openings
    for pos, char in enumerate(code):
        if char in naivePairs.keys(): openBraceStack.append(pos)            # if char is '{', push it into the 'openBraceStack'
        elif char in naivePairs.values(): pairs[openBraceStack.pop()] = pos # if char is '}', pop the last '{' from 'openBraceStack' and store this pair into 'pairs'
    
    return pairs

Usage (Have also provided in it's docstring):

bracePairs = makePairs(code)
for open, close in bracePairs.items():
   print(code[open : close+1], '\n\n\n')

Query specific usage:

bracePairs = makePairs(code)
cakeOpen = code.find('{', code.find('fun cake'))            # find the first '{' after cake function
cakeCode = code[cakeOpen + 1 : bracePairs[cakeOpen]]
print(cakeCode)

It worked, thanks. I just made a module using this way for my ease :) — Xephonine, Jan 17 '22 at 07:27
Cheers!, creating modules is the best approach to programming — HIMANSHU PANDEY, Jan 17 '22 at 07:45

Python: Get part of string between appropriate braces and symbols

1 Answers1

Here's a general purpose library function I've created for you

Usage (Have also provided in it's docstring):

Query specific usage: