a= 6/5j
print(a)
It prints -1.2j. Why it is a negative value in Python?
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jonrsharpe
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Rooney
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4Your question seems to be related to the maths, not the programming. – jonrsharpe Jan 11 '22 at 09:54
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In python, you can be more explicit about the intent of a complex number by using the type as a constructor. `complex(real, imaginary)`, so in your case I believe you intended `complex(0, 6/5j)`. – ChrisOram Jan 11 '22 at 09:56
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What else were you expecting? – MisterMiyagi Jan 11 '22 at 09:57
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3Oh, did you mean `(6/5)*1j` instead of `6/(5j)`? – khelwood Jan 11 '22 at 09:58
2 Answers
4
More of a math question, but the answer is
6/(5j) = 6j/(5jj) = 6j/(-5) = -1.2j
In general, 1/j = j/(jj) = -j
timgeb
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In python, a complex literal is (floatnumber | digitpart) ("j" | "J") with an optional real part in front of it. Therefore in
6/5j
5j is interpreted as a complex literal, which makes the calculation result correct (see other answers). To have a "lonely" j in your calculation, you always need to add a 1 in front of it:
6/5*1j
This does differ from how e.g. wolframalpha would handle the same input.
FlyingTeller
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