What function could be workaround of this Scratch block in Python?

Question

I want to know, what is a workaround/replacement for this Scratch block:

(letter (...) of (...))

In Python. I know that in JavaScript, the answer is:

"..."[... - 1]

could you please explain the ask in more detail; i'm not familiar with javascript and I don't get what is it that you want — Abhishek Jain, Jan 03 '22 at 13:11
@RixTheTyrunt i know being told that you should do research and tests yourself before asking sounds irritating at first but it is a fact really. — LercDsgn, Jan 03 '22 at 19:16
@RixTheTyrunt [Answering your own question](https://stackoverflow.com/help/self-answer) is accepted, even encouraged. But don't use a comment for that; please post an answer. Oh, and using capitals doesn't make the message clearer. — Ruud Helderman, Jan 04 '22 at 13:20
@RuudHelderman OK, but why can I only accept my answer in 2 hours? — RixTheTyrunt, Jan 05 '22 at 10:22
@RixTheTyrunt SO policies are discussed on [meta]. As has been done here: https://meta.stackoverflow.com/questions/277960/why-cant-you-accept-your-own-answer-immediately — Ruud Helderman, Jan 05 '22 at 11:12

score 0 · Accepted Answer · answered Jan 05 '22 at 10:19

The code is the same as in JavaScript, like:

var alphabet = "ABCDEFGHIJKLNOPQRSTUVWXYZ"
var letter1 = alphabet[0]
var letter2 = alphabet[1]
var letter3 = alphabet[2]
var letter123 = letter1 + letter2 + letter3

alert("The first three letters of the alphabet are: " + letter123)

I was very d**b

What function could be workaround of this Scratch block in Python?

1 Answers1