Passing a URL with brackets to curl using bash script

Asked Jan 03 '22 at 00:50

Active Jan 03 '22 at 00:50

Viewed 1,701 times

I am trying to get the response from a curl url only for a particular value. For example i am using the command

URLS=$(curl -g -H "Authorization: ${abc}" "https://api.buildkite.com/v2/organizations/org/agents?meta_data=[queue=dev]")

echo "${URLS}"

The metadata is actually as below:

"meta_data": [
      "queue=dev"
    ]

The above curl command is giving the response for all agents in all queues and not able to get the required ones specific to queue=dev.

What is the correct way to pass url with brackets?

asked Jan 03 '22 at 00:50

avk

I don't see anything in the documentation for the [Agents API](https://buildkite.com/docs/apis/rest-api/agents) that suggests you can pass metadata in a query like this. – chepner Jan 03 '22 at 01:07
Try with \ before each bracket. – Nic3500 Jan 03 '22 at 01:07
The metadata you show is part of the JSON *response* returned that describes a given agent. – chepner Jan 03 '22 at 01:08
From online docs. meta_data Filters the results by the given meta_data. Example: ?meta_data[some-key]=some-value – ufopilot Jan 03 '22 at 06:48
Have you tried to use single quotes for the URL (not for the header)? – Alessandro Argentieri Jan 03 '22 at 14:27

0 Answers0