favorite I have a UI in which when I select an item (in a tree) and then press a button "add", I get a new editor. With each item I can get an editor. (but all have the same ID) My purpose is to close only the editor of item1, for example, when I press "save". I'm able to close all the editors with: getSite().getWorkbenchWindow().getActivePage().closeAllEditors(true); But not only the one that I need to close. The following solution helped me:
// Creating and opening
MyObject item1 = ... //create item1
// open editor
myInput = new MyEditorInput(item1)
IDE.openEditor(workbenchPage, myInput, MY_EDITOR_ID);
// Closing
tmpInput = new MyEditorInput(item1)
IEditorReference[] editorReferences = PlatformUI.getWorkbench()
.getActiveWorkbenchWindow().getActivePage()
.getEditorReferences();
List<IEditorReference> relevantEditors = new ArrayList<IEditorReference>();
for (IEditorReference iEditorReference : editorReferences) {
if (iEditorReference.getEditorInput().equals(tmpInput)) {
relevantEditors.add(iEditorReference);
}
}
PlatformUI
.getWorkbench()
.getActiveWorkbenchWindow()
.getActivePage()
.closeEditors(
(IEditorReference[]) relevantEditors.toArray(new IEditorReference[relevantEditors
.size()]), true);
….but I still have some problems... As I can open many editors in the same time, and all of them have the same button "save", it happens that I press "save" in editor1 but close editor3... Actually, I save the last editor to be open (thanks to its "item")... this is the problem.. So I'm wondering if there is a way to identify the editor in which the button exists, so that I close it.. Thanks a lot I appreciate any help or hint (Sorry if my questions look easy and not worth being asked, but I'm still a beginner...)