for this command
$ grep ^r lab3.tr | grep "2 6" -c | awk "{s+=$6}END{print s}"
I am getting this error
awk: line 1: syntax error at or near }
and what does "h" stand for in the following line of trace file
h 0.106 1 7 cbr 100 ------- 1 1.0 5.0 6 6
You are using soft quotes around your awk-code so the shell interprets $6. As this argument is either empty or an unusable value, you receive said error. Use hard quotes for awk-code instead.
Example:
$echo 1 2 3 | awk "{print $1}"
1 2 3
=> shell interprets $1, however it is empty and thus only print is executed and it outputs the whole record.
$echo 1 2 3 | awk '{print $1}'
1
=> awk interprets $1 as field in record and thus it outputs the first field.
