I have a GitLab API (v4) that I need to call to get a project sub-directory (something apparently new in v.14.4, it seems not yet included python-gitlab libs), which in curl can be done with the following command:
curl --header "PRIVATE-TOKEN: A_Token001" http://192.168.156.55/api/v4/projects/10/repository/archive?path=ProjectSubDirectory --output ~./temp/ProjectSubDirectory.tar.gz
The issue is in the last part, the --output ~./GitLab/some_project_files/ProjectSubDirectory.tar.gz
I tried different methods (.content, .text) which failed, as:
...
response = requests.get(url=url, headers=headers, params=params).content
# and save the respon content with with open(...)
but in all the cases it saved a non-valid tar.gz file, or other issues.
I even tried https://curlconverter.com/, but the code it generates does not work as well, it seems ignoring precisely the --output parameter, not showing anything about the file itself:
headers = {'PRIVATE-TOKEN': 'A_Token001',}
params = (('path', 'ProjectSubDirectory'),)
response = requests.get('http://192.168.156.55/api/v4/projects/10/repository/archive', headers=headers, params=params)
For now, I just created a script and call it with sub-process, but I don't like much this approach due to Python has libraries, as requests, that I guess should have some way to do the same...