I need to connect to Snowflake using SQLAlchemy but the trick is, I need to authenticate using OAuth2. Snowflake documentation only describes connecting using username and password and this cannot be used in the solution I'm building. I can authenticate using Snowflake's python connector but I see no simple path how to glue it with SQLAlchemy. I'd like to know if there is a ready solution before I write a custom interface for this.
Asked
Active
Viewed 1,816 times
3
2 Answers
3
Use snowflake.connector.connect
to create a PEP-249 Connection to the database - see documentation. Then use param creator
of create_engine
(docs) - it takes a callable that returns PEP-249 Connection. If you use it then URL param is ignored.
Example code:
def get_connection():
return snowflake.connector.connect(
user="<username>",
host="<hostname>",
account="<account_identifier>",
authenticator="oauth",
token="<oauth_access_token>",
warehouse="test_warehouse",
database="test_db",
schema="test_schema"
)
engine = create_engine("snowflake://not@used/db", creator=get_connection)

minder
- 2,059
- 5
- 24
- 39
0
I got this working but just adding more params in the connection URL:
from sqlalchemy.engine import create_engine
import urllib.parse
connection_url = f"snowflake://{user}:@{account}/{database}/{schema}?warehouse={warehouse}&authenticator=oauth&token={urllib.parse.quote(access_token)}"
engine = create_engine(connection_url)
with engine.begin() as connection:
print(connection.execute('select count(*) from lineitem').fetchone())
If you don't want to be constructing the URL on your own, you can use snowflake.sqlalchemy.URL
like this:
from snowflake.sqlalchemy import URL
connection_url = URL(
user=user,
authenticator="oauth",
token=access_token,
host=host,
account=account,
warehouse=warehouse,
database=database,
schema=schema
)

Jan Stastny
- 143
- 1
- 7