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I am using Android App Links to take users to a specific screen directly in my app. I am following the same approach as Rakuten, meaning the last path segment(LPs) of the URL is a valid domain, which lands users to a specific brand screen on my app.

https://www.rakuten.com/nike.com   (lps = nike.com)
https://www.rakuten.com/adidas.com   (lps = addidas.com)
https://www.rakuten.com/samsung.com   (lps = samsung.com)

Android Manifest Code

<data android:host="www.rakuten.com" android:scheme="https" android:pathPattern=".*..*"/>

The pathPattern = ".*..*" allows any domain in the URL to open inside my app. All of the below links open Nike brand screen in my app.

https://www.rakuten.com/dir1/nike.com
https://www.rakuten.com/dir1/dir2/nike.com
https://www.rakuten.com/dir1/dir2/dir3/nike.com
https://www.rakuten.com/dir1/dir2/dir3/dir4/nike.com

CASE TO HANDLE:

if any URL contains /browser/ (meaning subdirectory name = browser), I want to open that URL in the browser and not inside my app.

https://www.rakuten.com/browser/nike.com (should open in browser and not in-app)

Is there any possibility to do that?

Suraj Rao
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shanraisshan
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2 Answers2

1

Unfortunately we can't exclude any certain url, since Android doesn't provide that option.

The best practice is to give as precise pathPrefix as possible.

<data android:scheme="https"
      android:host="www.rakuten.com"
      android:pathPrefix="/dir1/" />

So it will open https://www.rakuten.com/dir1/* links

Pramod Waghmare
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0

try using:

<data android:host="www.rakuten.com/app" android:scheme="https" android:pathPattern=".*..*"/>

All routes that you want to open in app should live under www.rakuten.com/app

All routes that you want to open in browser should live under www.rakuten.com/

Eyal Gofer
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