Java: Printing out all the integers in args array

Question

How do I print out a set of integers from my args variable in Java?

I tried:

System.out.println("The numbers are " + args.length);

But all that does is print out the number of elements in the array.

I want it so that if there are 5 arguments passed: 1 2 3 4 5 the output should be:

1, 2, 3, 4, 5

score 12 · Answer 1 · answered Aug 10 '11 at 10:43

12

Take a look if you like

  System.out.println("The numbers are "+Arrays.toString(args));

If not, you'll have to loop over the array and format it yourself.

answered Aug 10 '11 at 10:43

Thilo

does `Arrays.toString` print with the intermediate ","'s ? – Foo Bah Aug 10 '11 at 20:38
yes, but also with (possibly unwanted) brackets around the list – Thilo Aug 10 '11 at 23:44

score 2 · Answer 2 · edited Aug 10 '11 at 17:54

2

But all that does is print out the numbers in the array not the numbers separately.

This seems to be somewhat unclear.

args.length gives the length of the array rather than its elements.

Use a for loop:

System.out.println("The numbers are ");

for(int i=0; i < args.length; i++)
    System.out.print(args[i] + " ");

edited Aug 10 '11 at 17:54

Jason Plank

answered Aug 10 '11 at 11:03

Shraddha

The compiler gives me an error of "i cannot be resolved to a variable" When i resolve it with "int b = 0;" it gives me a single integer, rather than the integers in args. – syncoroll Aug 10 '11 at 11:17

score 2 · Answer 3 · answered Aug 10 '11 at 16:58

2

Try:

for(String arg: args)
    System.out.print(arg + " ");

answered Aug 10 '11 at 16:58

Marcelo

1

@MByD Your deducing powers are powerful, mine point me to `public static void main(String[] args)` – Marcelo Aug 10 '11 at 17:02
Then why did you add `+ " "` ? – MByD Aug 10 '11 at 17:05
2

@MByD To print out a **space** between each arg. – Marcelo Aug 10 '11 at 17:09

3 Answers3