Get parent node name in anytree

Question

I have created a tree using anytree for my custom taxonomy and I am able to search the tree using:

from anytree import find
name='c'
find(root, lambda node: node.name == name)

This returns an object of Node class that looks something like this:

Node('/f/b/d')

So, for child c, d is the immediate parent and I just want to extract 'd' and not the entire path mentioned above.

Any help would be appreciated :)

I don't know `anytree` but maybe it could search `node.next.name == name` — furas, Nov 23 '21 at 01:52

furas · Accepted Answer · 2021-11-23T09:17:26.137

2

You can get .parent.name

You can even get grandparent name .parent.parent.name (if only exists)

from anytree import Node
from anytree import find

root = Node("f")
b = Node("b", parent=root)
d = Node("d", parent=b)
c = Node("c", parent=d)

name='c'
result = find(root, lambda node: node.name == name)

print('result Node:', result)

if result.parent:
    print('parent name:', result.parent.name)

if result.parent and result.parent.parent:
    print('grandparent:', result.parent.parent.name)

Result:

result Node: Node('/f/b/d/c')
parent name: d
grandparent: b

edited Nov 23 '21 at 09:17

answered Nov 23 '21 at 01:57

furas

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Thank you so much! it works for me. – satish silveri Nov 23 '21 at 18:29

score 1 · Answer 2 · answered Nov 23 '21 at 00:30

1

Three things to note:

you can cast anytree.Node to a string
the first 6 characters of the stringified Node class is always Node(' and the last 2 characters are always ')
the anytree.Node class has a separator attribute which you can use to split the stringified Node on

Combining these facts:

In [7]: node
Out[7]: Node('/A/C')

In [8]: str(_next)[6:-2].split(_next.separator)[-1]
Out[8]: 'C'

answered Nov 23 '21 at 00:30

aweeeezy

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Thank you for the response. @furas answer is more accurate and what i was looking for :) – satish silveri Dec 01 '21 at 20:52

Get parent node name in anytree

2 Answers2