how to define types as interfaces in Typescript

Question

I have many parts in my code where I define specific types like this:

function foo (state: "open" | "closed") { ... }

I want to know if there is a way to define that type like interfaces. something like:

type State: "open" | "closed";

so I can use it in a clearer way:

function foo (state: State) { ... }

Yes, you want a [type alias](https://www.typescriptlang.org/docs/handbook/2/everyday-types.html#type-aliases) of the form `type State = "open" | "closed"`. — jcalz, Nov 02 '21 at 17:04

score 0 · Accepted Answer · answered Nov 02 '21 at 17:06

0

You can use type. You are almost there:

type State = "open" | "closed";

function foo (state: State) { console.log(state); }
foo("open"); 
foo("openx"); //Error
foo("closed");

answered Nov 02 '21 at 17:06

Tushar Shahi

1 Answers1