Issues storing arguments from getopts in shell script

Question

I am new using unix and I recently tried to create a code that would take some arguments and pass it to a python script and later use those arguments for downstream processes.

I am trying to use getopts but after I tried running the script it looks like my arguments were not stored in variables and anything downstream failed.

This is a piece of what I tried so far

#!/bin/bash
function usage() {
    cat <<USAGE

    Usage: $0 [-f fasta] [-o output name] [-m memory] [-t time] [-n number of tasks] [-c cores] [-g gpus] [-e extra]

    Options:
        -f  fasta file
        -o  output name
        -m  memory to request
        -t  time to request
        -n  number of tasks
        -c  cores to request
        -g  gpus to request - no more than 4!
        -e  extra arguments for program
USAGE
}

while getopts ":f:o:m:t:n:c:g:e:h" flag
do
    case "${flag}" in
        f)
          fasta=${OPTARG}
            ;;
        o)
          out_name=${OPTARG}
            ;;
        m)
          memory=${OPTARG}
            ;;
        t)
          time=${OPTARG}
            ;;
        n)
          number=${OPTARG}
            ;;
        c)
          cores=${OPTARG}
            ;;
        g)
          gpus=${OPTARG}
            ;;
        e)
          extra=${OPTARG}
            ;;
        h)
          usage
            ;;
        :)
          echo "Invalid option: $OPTARG" 1>&2
          usage
          exit 1
            ;;
        \?)
            echo "Invalid option"
            usage
            exit 1
            ;;
    esac
done

python3 /scratch/amolinav/programs/my_script_single.py ${fasta} ${out_name} ${memory} ${time} ${number} ${cores} ${gpus} ${extra}

I would really appreciate if someone could point out where I am making the mistake. Thank you so much in advance for your help