Update 2: I suspect the question gets upvoted because of the possible solution that I describe. Highlighted it for clarity.
Update 1: This question gets a lot of views. If you think the question can be enhanced with the situation in which you encountered the error yourself, please briefly describe your situation in the comments so we can make this Q&A more valuable. And if you have a solution to your version of the problem, please add it as an answer.
I want to update the UI after doing async background work using Task.detached
and an async
function.
However, I get a build error Reference to captured var 'a' in concurrently-executing code
error during build.
I tried some things and turning the variable into a let constant
before updating the UI is the only thing that works. Why do I need to make a let constant before being able to update the UI? Are there alternatives?
class ViewModel: ObservableObject {
@Published var something: String?
init() {
Task.detached(priority: .userInitiated) {
await self.doVariousStuff()
}
}
private func doVariousStuff() async {
var a = "a"
let b = await doSomeAsyncStuff()
a.append(b)
something = a /* Not working,
Gives
- runtime warning `Publishing changes from
background threads is not allowed; make sure to
publish values from the main thread (via operators
like receive(on:)) on model updates.`
or, if `something` is @MainActor:
- buildtime error `Property 'something' isolated
to global actor 'MainActor' can not be mutated
from this context`
*/
await MainActor.run {
something = a
} /* Not working,
Gives buildtime error "Reference to captured var 'a'
in concurrently-executing code" error during build
*/
DispatchQueue.main.async {
self.something = a
} /* Not working,
Gives buildtime error "Reference to captured var 'a'
in concurrently-executing code" error during build
*/
/*
This however, works!
*/
let c = a
await MainActor.run {
something = c
}
}
private func doSomeAsyncStuff() async -> String {
return "b"
}
}