Proper way to store an url in xml?

Question

I am storing data in xml file, In one of the node I have to store an url which consists of special character like & I used &amp instead of & and xml shows no error but when I did SAX parsing String value returned within the node is the string which is after &,

I am guessing the way I am storing the url is not proper.

What is right way of storing an url in xml.

Currently I am storing as,

<param>http://www.example.com?param1=abc&amp;v=1</param>

XML has no errors, but SAX parser won't return the whole url.

EDIT: I have semicolon after &amp in the url, I missed it the first time.

Solution: It was not the problem with XML , but the way I handled XML in XMLHandler,
I was using new String(ch,start,length);
Now changed to stringBuilder();

score 3 · Answer 1 · edited May 23 '17 at 12:06

3

You need a semicolon (;) after the &amp:

<param>http://www.example.com?param1=abc&amp;v=1</param>

EDIT: Okay, now that this has been clarified a bit, I think the issue is that SAX doesn't have to return the entire string in a single characters() call. See this question for more information on how to resolve this.

edited May 23 '17 at 12:06

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answered Aug 04 '11 at 14:15

Adam Batkin

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Sorry, I missed ; , I have updated the question. I have semicolon in the url. – sat Aug 04 '11 at 14:17
@sat: Well, in that case your SAX parser should be returning the whole string. What *does* the SAX parser return? – Adam Batkin Aug 04 '11 at 14:18
It returns me v=1 with above url being parsed in SAX – sat Aug 04 '11 at 14:20
I got the solution, it was buffering problem. fixed it in SAXHandler itself. – sat Aug 04 '11 at 14:26

score 3 · Accepted Answer · edited May 23 '17 at 11:57

3

Your XML is correct (now that you have added the semi-colon), so your use of the SAX API must be wrong.

Maybe see the following answer: Sax parsing and encoding

edited May 23 '17 at 11:57

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answered Aug 04 '11 at 14:20

Matthew Wilson

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It worked, Thank you :) After 4 min, I will mark the answer as correct :) – sat Aug 04 '11 at 14:26

score 0 · Answer 3 · answered Aug 04 '11 at 14:16

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if ampv is param then:

<param>http://www.example.com?param1=abc&amp;ampv=1</param>

else if v is param:

<param>http://www.example.com?param1=abc&amp;v=1</param>

answered Aug 04 '11 at 14:16

Subdigger

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Proper way to store an url in xml?

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