Appending hex values to a list/converting string lists to hex

Question

I have a dataframe where each row is a CAN message which has to be in hex. But when I put the rows into a list, individual values are stored as strings. For example:

['0x0', '0x0', '0x0', '0x0', '0x0', '0x0', '0x0', '0x1']

Is there a way to have [0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x1] instead?

So you want to retain the objects type? Can you post the `type()` of the object? — The Singularity, Sep 21 '21 at 05:30
Python represents hex literals as their denary values, for example `[0x01, 0x02]` as `[1, 2]` so you have to choose between strings or normal integers. — snakecharmerb, Sep 21 '21 at 13:01

score 1 · Accepted Answer · answered Sep 21 '21 at 05:33

Easy enough! Use the base parameter on the int function to convert from hex string to integer, and you can use hex to go back from integer to hex string.

# Convert hex string to int
str_vals = ['0x0', '0x0', '0x0', '0x0', '0x0', '0x0', '0x0', '0x1']
int_vals = [int(val, 16) for val in str_vals]

# Convert int to hex string
int_vals = [0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x1]
str_vals = [hex(val) for val in int_vals]

Appending hex values to a list/converting string lists to hex

1 Answers1