What does {foo:>7f} do in Python f-strings?

Question

In particular, this is over my head:

print(f"foo: {foo:>7f}, bar: {bar:>5d}")

I can imagine that f indicates float and d indicates integer but I don't really understand what the >7f and >5d do.

Note that I understand what

print(f"foo: {foo}, bar: {bar}")

does.

in python3.9+ this can be shortened to `f"{=foo:>7f} {=bar:>5f}"` :P — Joran Beasley, Sep 19 '21 at 18:41
Did you look at [the docs](https://docs.python.org/3/library/string.html#format-specification-mini-language)? — wjandrea, Sep 19 '21 at 18:43
Yes I did but couldn't understand. Even though I understand now due to the answer I still find the wording confusing for me. — Essam, Sep 19 '21 at 18:49
@Joran I think you have the equals in the wrong place. `f"{foo=:>7f} {bar=:>5f}"` — wjandrea, Sep 19 '21 at 19:04

score 4 · Accepted Answer · edited Sep 19 '21 at 19:01

It means that the resulting string from {foo:>7f} should at least be of width 7, meaning that if it were 4 characters/digits long, then spaces would be appended to its left.

>>> foo = 1234
>>> bar = 100
>>> f"foo: {foo:>7d}, bar: {bar:>5d}"
'foo:    1234, bar:   100'

Note the spaces are before each number.

>>> f"foo: {foo:>4d}, bar: {bar:>5d}"
'foo: 1234, bar:   100'

Notice how the first number isn't affected because it has width of 4.

What does {foo:>7f} do in Python f-strings?

1 Answers1