initial value error while using gradient descent algorithm

Question

Problem: Initial value is 10000 and the solution is converging to 10000 instead of actual solution 1.

import numpy.linalg as nl
x_ini=10000

def obj(x):
    f = x**2 - 2*x + 3
    return f

def grad(x):
    df = 2*x - 2
    return df

n_iter=1000
lr=0.001

x_old = x_ini


for _ in range(True):
    
    x_new = x_old - lr*(grad(x_old))
    x_old = x_new
    
    if(nl.norm(grad(x_old))<=1e-03):
        break
    x_new = x_old
    
print(x_new)

`for _ in range(True)` will run exactly once – ddejohn Sep 17 '21 at 05:22 — ddejohn, Sep 17 '21 at 05:22

score 0 · Accepted Answer · answered Sep 17 '21 at 05:51

0

while True:
    
    x_new = x_old - lr*(grad(x_old))
    x_old = x_new
    y = nl.norm(grad(x_old))
    if(y<=1e-03):
        break
    x_new = x_old

print(x_new)

You can change for to while

answered Sep 17 '21 at 05:51

tanmay2893

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initial value error while using gradient descent algorithm

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