How to set ticks in Seaborn FacetGrid?

Question

I have a code like this, and I want to add ticks on the X-axis so I could see better what the value over 150 corresponds to, for example. the range for my X-values is from 178 to 17639.

bins = np.linspace(df.days_with_cr_line.min(), df.days_with_cr_line.max(), 32)

g = sns.FacetGrid(df, col="loan_status", hue="loan_status", palette=['#8856a7', '#f03b20'], col_wrap=2)
g.map(plt.hist, 'days_with_cr_line', bins=bins, ec="k")

I have tried

g.set_xticks(np.arange(0,18000,500), minor=True)
AttributeError: 'FacetGrid' object has no attribute 'set_xticks'

and

for axes in g.axes.flat:
    _ = axes.set_xticks(axes.get_xticks(range(0,18000)))

this removes the tick labels without adding any ticks.

score 3 · Accepted Answer · answered Aug 31 '21 at 12:56

If you use set to set the number of ticks on the x-axis, and then set the tick labels for them, you will get the intended result. The data is created appropriately.

import pandas as pd
import numpy as np
import seaborn as sns
import matplotlib.pyplot as plt

np.random.seed(20210831)
df = pd.DataFrame({'days_with_cr_line':np.random.randint(10,1000,size=1000),
                  'loan_status':np.random.choice(['Fully paid','Not fully paid'], size=1000)})
bins = np.linspace(df.days_with_cr_line.min(), df.days_with_cr_line.max(), 32)

g = sns.FacetGrid(df, col="loan_status", hue="loan_status", palette=['#8856a7', '#f03b20'], col_wrap=2)
g.map(plt.hist, 'days_with_cr_line', bins=bins, ec="k")
g.set(xticks=np.arange(0,1050,50))
g.set_xticklabels(np.arange(0,1050,50), rotation=90)

How to set ticks in Seaborn FacetGrid?

1 Answers1