How to evaluate Julia's anonymous functions for a value from an expression

Asked Aug 25 '21 at 18:05

Active Aug 25 '21 at 18:05

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I am trying to establish a group of anonymous functions to later call and receive a value from.

Here is a basic working example of the problem I'm facing.

expr = :(x+y)
f = eval((x,y,z)->expr)

This gives me the following response...

Then when I try to call it to be evaluated I just get the expression back.

f(1,2,3)

I would expect it to return 3 but instead it returns the original expression. How do I get it to evaluate the expression inside the anonymous function as it has been constructed here?

Thanks

asked Aug 25 '21 at 18:05

Sean C

5

`f = eval(:((x,y,z)->$expr))`. So you construct an expression that defines your function and interpolate `expr` into it. – pfitzseb Aug 25 '21 at 18:15
Thank you that works great! – Sean C Aug 25 '21 at 18:31
@pfitzseb maybe you could post it as an answer? will be more readable by the others :-) – Przemyslaw Szufel Aug 26 '21 at 23:16

How to evaluate Julia's anonymous functions for a value from an expression

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