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I am trying to solve the following system of equations:

{a*[1+b*(5+c)]}^(-1/2) = 2388;

{a*[1+b*(5+c)]}^(-1/2) = 2633;

{a*[1+b*(5+c)]}^(-1/2) = 2763;

for which I need to get the values of a, b and c. Can anyone advise on how to proceed? I'm not sure which MATLAB function to use, i tried a normal "solve" as

syms x y z 

eqn1 = (x*(1+y*(5+z)))^(-1/2) == 2388;
eqn2 = (x*(1+y*(5+z)))^(-1/2) == 2633;
eqn3 = (x*(1+y*(5+z)))^(-1/2) == 2763;

solutions = solve([eqn1 eqn2 eqn2],(x,y,z));

but it clearly doesn't work. Any suggestions?

Lorenzo Metilli
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  • your equations are impossible? how could a single value for x,y,z produce, in the exact same equation, 3 values? a=1, a=2 is an imposible set of equations, its either one, or the other. Its the same with yours. You need 3 equations to solve your system, but you only have 1 equation, with 3 different results after applying it – Ander Biguri Aug 19 '21 at 12:06

1 Answers1

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The first issue is what @AnderBiguri already mentioned: The same expression cannot simultaniously have multiple values, so there is no hope of actually finding a solution.

The second part is that your syntax is incorrect: Lists/Arrays must be written with square brackets instead of parenthesis, as the error message that you get by running this is probably gonna tell you. I recommend reading the example from the documentation.

flawr
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