How to make a Password Generator from User using list?

Question

I am trying to create a random password generator in python .

How do I select like 3 or 4 or 5 random number from a list using user.

For example :

numbers = ['0','1','2','3,','4','5','6','7','8',9']

numbers_in = int(input('how many numbers would you love to be in your password:').

If i choose 4 as a user how will get four random numbers from a list like 4791

Does this answer your question? [Generate password in python](https://stackoverflow.com/questions/3854692/generate-password-in-python) — Benoît Zu, Aug 18 '21 at 08:39

Roman Pavelka · Answer 1 · 2021-08-18T11:20:46.010

1

Here you go:

>>> from random import choice
>>> from string import digits
>>> N = int(input('How many numbers would you love to be in your password: '))
How many numbers would you love to be in your password: 4
>>> "".join(choice(digits) for _ in range(N))
'1786'

Shorter version of the last statement provided by @furas in comments:

"".join(choices(digits, k=N))

edited Aug 18 '21 at 11:20

answered Aug 18 '21 at 08:43

Roman Pavelka

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You don't need a list. ```join``` takes in an iterable. ```"".join(choice(digits) for _ in range(5))``` – Aug 18 '21 at 08:44
@Sujay, thanks, your improvement is added :) – Roman Pavelka Aug 18 '21 at 08:47
1

shorter `choices(digits, k=N)` - (with char `s` in word `choices`) – furas Aug 18 '21 at 10:57
@furas, nice! I didn't know this :) – Roman Pavelka Aug 18 '21 at 11:19

How to make a Password Generator from User using list?

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