Java How to remove carriage return (HEX 0A) from String?

Question

If a particular String contains a newline character that is invisible (not \n but is 0A in hexadecimal because this value is passed down from the database), how can i able to chomp it away? Will Apache Chomp help?

http://commons.apache.org/lang/api-2.5/org/apache/commons/lang/StringUtils.html#chomp(java.lang.String)

The hex form of the text returned from the database is "5761 6920 4D61 6E0D 0A"

It translates to "Wai Man" with a carriage return.

`\n` **is** U+000A (a.k.a newline). Could you tell us **exactly** what your `String` looks like? Best provide a `char`-for-`char` dump of it. — Joachim Sauer, Jul 29 '11 at 09:02
Hi joachi, it is returned as "5761 6920 4D61 6E0D 0A" for "Wai Man", a person's name. — Oh Chin Boon, Jul 29 '11 at 09:05
This is simply "Wai Man" with a tailing `\r\n` (i.e. a DOS/Windows-style newline). `input.replace("[\r\n]+$", "")` should get rid of any tailing newlines on your input. — Joachim Sauer, Jul 29 '11 at 09:09
No, [Unix uses a simple `\n` (a.k.a LF)](http://en.wikipedia.org/wiki/Newline). — Joachim Sauer, Jul 29 '11 at 09:26

score 5 · Accepted Answer · answered Jul 29 '11 at 09:02

5

You can use a regular expression

String text = "Hello\r\nThere\r\n";
String shortText = text.replaceAll("\r", "");

answered Jul 29 '11 at 09:02

Peter Lawrey

525,659
79
751
1,130

score 0 · Answer 2 · edited Mar 15 '22 at 07:16

0

This is what I did and it worked for me:

input_data.replaceAll("\\xC2"," ").replaceAll("\\xA0"," ")

edited Mar 15 '22 at 07:16

Procrastinator

2,526
30
27
36

answered Mar 11 '22 at 16:55

Tarun Agrawal

1

Java How to remove carriage return (HEX 0A) from String?

2 Answers2

Linked