Is their any way I can not round off the number while using parseInt?

Question

let display = '5+10.10';
let numbers = display.match(/(\d+\.?\d*|\.\d+)/g).map(a => parseInt(a));
console.log(numbers)//returns [5, 10]

when I don't use parseInt:


let display = '5+10.10';
let numbers = display.match(/(\d+\.?\d*|\.\d+)/g);
console.log(numbers)//returns ["5", "10.10"]

I need the array item's as an number with decimal rather than a string.

Do you know what an interger / int is? It is a whole number, no matter what. If you want floating point numbers use `parseFloat` instead. — luk2302, Aug 04 '21 at 08:22
`let numbers = display.match(/(\d+\.?\d*|\.\d+)/g).map(Number);` — Hao Wu, Aug 04 '21 at 08:24

score 1 · Answer 1 · answered Aug 04 '21 at 08:24

1

let numbers = display.match(/(\d+\.?\d*|\.\d+)/g).map(Number);

you can use the broader Number here, because an integer by definition will never have a decimal part.

answered Aug 04 '21 at 08:24

thinkgruen

score 0 · Accepted Answer · answered Aug 04 '21 at 08:23

0

parseInt converts to Integer. You want parseFloat :

let display = '5+10.10';
let numbers = display.match(/(\d+\.?\d*|\.\d+)/g).map(a => parseFloat(a));
console.log(numbers)

answered Aug 04 '21 at 08:23

Tushar Shahi

Is their any way I can **not** round off the number while using parseInt?