Json output array to php variable

Question

prob an easy fix, but I'm stuck.

So print_r($data) =

stdClass Object (
    [code] => 200000
    [data] => stdClass Object (
        [accountEquity] => 111
        [unrealisedPNL] => 111
        [marginBalance] => 111
        [positionMargin] => 111
        [orderMargin] => 0
        [frozenFunds] => 0
        [availableBalance] => 111
        [currency] => xxx
    )
)

And echo $data->code outputs '20000'

But I can not get the other 'variables' to work. Ive tried:

$data->code->data->accountEquity

$data[1]->accountEquity

$data->code->data->accountEquity

What is the right format to get those other values?

Thank you. gr Mike

Try restructuring your debug output, you'll see the solution pretty quickly then (I have edited your question). Otherwise, it would most likely help you to use a debugger for whatever IDE you are working with. Just Google "debug php with [your ide here]" — Aram Becker, Jul 28 '21 at 10:52
Welcome to Stackoverflow. Please read how to [ask a good question](https://stackoverflow.com/help/how-to-ask) and provide a [minimal reproducible example](https://stackoverflow.com/help/minimal-reproducible-example) preferably in a [Stack snippet](https://stackoverflow.blog/2014/09/16/introducing-runnable-javascript-css-and-html-code-snippets/) — Timothy Alexis Vass, Jul 28 '21 at 16:01

score 1 · Answer 1 · answered Jul 28 '21 at 07:48

1

The best way to get accountEquity is

$data->data->accountEquity

answered Jul 28 '21 at 07:48

Rahul

35
5

score 0 · Answer 2 · answered Jul 28 '21 at 07:25

0

The right way to access accountEquity is:

$data->data->accountEquity

But you could also cast the object to an array with:

$data = (array) $data;

Then accountEquity is reached by:

$data['data']['accountEquity']

answered Jul 28 '21 at 07:25

wayneOS

1,427
1
14
20

Glad i could help and welcome to SO. Please select my answer so the question is finished. Happy coding. – wayneOS Jul 28 '21 at 07:30

Json output array to php variable

2 Answers2