I want to animate the trajectory of a circle (ball) defined by y = -t^2 + 11t - 18. Basically it would just be bouncing up and down (i.e. no change in x). Its intercepts are (2,0) and (9,0) so the animation should start at time t = 2 as it leaves the ground and end at time t = 9 as it returns to the ground. I am also hoping that a running display of the time could also be included in the animation. So basically between times t=0 and t=2, the ball would just be on the ground. This is the code I have so far but it doesn't seem to make sense. I'm not sure whether the animation is just going too fast.
%matplotlib notebook
import numpy as np
from matplotlib import pyplot as plt
from matplotlib import animation
fig = plt.figure()
fig.set_dpi(100)
fig.set_size_inches(3, 3)
ax = plt.axes(xlim=(0, 10), ylim=(0, 15))
patch = plt.Circle((5, 0), 0.2, fc='r')
def init():
patch.center = (5, 0)
ax.add_patch(patch)
return patch,
def animate(i):
x, y = patch.center
x = 0 * i+5
y = - i**2 + 11 * i - 18
patch.center = (x, y)
return patch,
anim = animation.FuncAnimation(fig, animate,
init_func=init,
frames=3600,
interval=1,
blit=True)
plt.show()
