Cannot read property 'sort' of undefined

Question

I was trying to reference an object (which is inside of an array) and there is an error:

Cannot read property 'sort' of undefined

This is my code:

const items = [
    { id: 1, value:5, weight: 14 },
    { id: 2, value:8, weight: 3  },
    { id: 3, value: 10, weight: 8},
    { id: 4, value: 2, weight: 4},
];

maxWeight = 15;

function sort(){
    let sort = 0;
    items.value.sort((a, b) => b - a);
    for(let i = 0; i < items.length; i++){
        console.log(items[i].value)
        sort += items[i].value;
        if(sort <= maxWeight){
            break;
        }
    }
    console.log(sort);
}

sort();

What did I do wrong? Did I reference an object incorrectly?

do you want to sort items by a subtraction of value key? – Filipe Mendes Jul 06 '21 at 05:55 — Filipe Mendes, Jul 06 '21 at 05:55
items is an array, there is no "value" property inside it – Filipe Mendes Jul 06 '21 at 05:56 — Filipe Mendes, Jul 06 '21 at 05:56

score 1 · Answer 1 · answered Jul 06 '21 at 05:57

1

items is an array, it doesn't have a value property. Instead, each element in it has such a property, and you can sort the array according to it:

items.sort((a, b) => b.value - a.value);

answered Jul 06 '21 at 05:57

Mureinik

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score 0 · Accepted Answer · answered Jul 06 '21 at 05:55

Check this to items.sort((a, b) => b.value - a.value); assuming you want to sort by value key

const items = [
    { id: 1, value:5, weight: 14 },
    { id: 2, value:8, weight: 3  },
    { id: 3, value: 10, weight: 8},
    { id: 4, value: 2, weight: 4},
];

maxWeight = 15;

function sort(){
    let sort = 0;
    items.sort((a, b) => b.value - a.value);
    //console.log(items);
    for(let i = 0; i < items.length; i++){
        console.log(items[i].value)
        sort += items[i].value;
        if(sort <= maxWeight){
            break;
        }
    }
    console.log(sort);
}

sort();

Cannot read property 'sort' of undefined

2 Answers2