Flutter Awesome Notification couldn't bind a method to action button

Question

I'm developing an app which needs to answer the notifications. I can display the button when I received the notification. However, I couldn't bind any method to it. Here is my code:

Future<void> firebaseMessagingBackgroundHandler(RemoteMessage message)  async {
  await Firebase.initializeApp();
    AwesomeNotifications().createNotification(
          content: NotificationContent(
              id: 10,
              channelKey: 'basic_channel',
              title: 'Simple Notification',
              body: 'Simple body'),
          actionButtons: [
            NotificationActionButton(
                label: 'TEST',
                enabled: true,
                buttonType: ActionButtonType.Default,
                key: 'test',
                )
          ]);
    print("Background message service");
  }

Thank you for your helps!

any solution on that? – Benyamin Beyzaie Jul 07 '21 at 22:24 — Benyamin Beyzaie, Jul 07 '21 at 22:24

score 2 · Accepted Answer · answered Jul 07 '21 at 22:46

2

You should create a event stream and listen to events like that:

    AwesomeNotifications().actionStream.listen((event) {
      print('event received!');
      print(event.toMap().toString());
      // do something based on event...
    });

answered Jul 07 '21 at 22:46

Benyamin Beyzaie

503
5
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outdated for the new version... – alperefesahin Oct 07 '22 at 17:54

score -1 · Answer 2 · answered Nov 27 '22 at 15:47

Update for anyone from the new versions. You can handle clicks on notifications with various other actions, by following the documentation. here's what I did. documentation

class NotificationController {
  /// Use this method to detect when the user taps on a notification or action button
  @pragma("vm:entry-point")
  static Future<void> onActionReceivedMethod(ReceivedAction receivedAction) async {
    // Your code goes here

    /// Handles regular notification taps.
    if(receivedAction.actionType == ActionType.Default){
      if(receivedAction.id == 17897583){
        // do something...
      }
    }
  }
}

Flutter Awesome Notification couldn't bind a method to action button

2 Answers2