What is the Sobel operator?

Question

I tried 5 different implementations of the Sobel operator in Python, one of which I implemented myself, and the results are radically different.

My question is similar to this one, but there are still differences I don't understand with the other implementations.

Is there any agreed on definition of the Sobel operator, and is it always synonymous to "image gradient"?

Even the definition of the Sobel kernel is different from source to source, according to Wikipedia it is [[1, 0, -1],[2, 0, -2],[1, 0, -1]], but according to other sources it is [[-1, 0, 1],[-2, 0, 2],[-1, 0, 1]].

Here is my code where I tried the different techniques:

from scipy import ndimage
import numpy as np
import cv2 as cv
from scipy import ndimage
from PIL import Image, ImageFilter

img = np.random.randint(0, 255, [10, 10]).astype(np.uint8)

def sobel_x(img) :
    return ndimage.convolve(img, np.array([[-1, 0, 1],[-2, 0, 2],[-1, 0, 1]]))

my_sobel = sobel_x(img)
_, numpy_sobel = np.gradient(img)
opencv_sobel = cv.Sobel(img, cv.CV_8UC1, 1, 0)
ndimage_sobel = ndimage.sobel(img, axis=0, mode="constant")
pil_sobel = np.array(Image.fromarray(img).filter(ImageFilter.Kernel((3, 3), (-1, 0, 1, -2, 0, 2, -1, 0, 1), 1, 0)))

print(my_sobel)
print(numpy_sobel)
print(opencv_sobel)
print(ndimage_sobel)
print(pil_sobel)

You may have a look at [this](https://www.youtube.com/watch?v=AXVo0UldlnQ) to get an idea how sobel implemented in opencv — Yunus Temurlenk, Jun 16 '21 at 04:50

Cris Luengo · Accepted Answer · 2021-06-15T18:13:15.967

The Sobel operator estimates the derivative.

The correct definition of the Sobel operator to estimate the horizontal derivative is:

  | 1  0 -1 |
  | 2  0 -2 | / 8
  | 1  0 -1 |

The division by 8 is important to get the right magnitude. People often leave it out because they don't care about the actual derivative, they care about comparing the gradient in different places of the same image. Multiplying everything by 8 makes no difference there, and so leaving out the /8 keeps things simple.

You will see the kernel defined with the inverse signs some places. These are cases where the kernel is applied by correlation instead of convolution (which differ by a mirroring of the kernel), such as the case of OpenCV. These can also be cases where people copy stuff without understanding them, resulting in a gradient with the wrong sign.

But then again, the Sobel operator is mostly applied to obtain the gradient magnitude (the square root of the sum of the squares of the horizontal and vertical derivatives). In this case, reversing the signs doesn't matter any more.

Note that np.gradient(img) is comparable to convolving with [1,0,-1]/2. This is another way to estimate the derivative. Sobel adds a regularization (==smoothing) in the perpendicular direction.

You will get a better understanding of each implementation if you use a more meaningful test image. Try for example a black image with a white square in the middle. You will be able to compare the strength of the estimated gradients, their direction (I assume some libraries use a different definition of x and y axes), and you will be able to see the effect of the regularization.

score 1 · Answer 2 · answered Jun 15 '21 at 14:22

according to wikipedia it's [[1, 0, -1],[2, 0, -2],[1, 0, 1]] but according to other sources it's [[-1, 0, 1],[-2, 0, 2],[-1, 0, 1]]

Both are used for detecting vertical edges. Difference here is how these kernels mark "left" and "right" edges.

For simplicity sake lets consider 1D example, and let array be

[0, 0, 255, 255, 255]

then if we calculate using padding then

kernel [2, 0, -2] gives [0, -510, -510, 0, 0]
kernel [-2, 0, 2] gives [0, 510, 510, 0, 0]

As you can see abrupt increase in value was marked with negative values by first kernel and positive values by second. Note that is is relevant only if you need to discriminate left vs right edges, when you want just to find vertical edges, you might use any of these 2 aboves and then get absolute value.

What is the Sobel operator?

2 Answers2