Embedded parameter substitution

Question

This is what parameter substitution would be one by one (transforming a picture file name into a date) :

var=“2020-12-30 11-30-55CX.mov”
p1=${var:0:11}
pt=${var:11:8}
p2=${pt//-/:}
dt=“${p1} ${p2}”

I want to do this in one shot, something like this so exiftool can take it:

dt=“${var:0:11} ${${var:11:8}//-/:}”

Don't use "smart quotes" when writing code. – Barmar May 28 '21 at 00:15 — Barmar, May 28 '21 at 00:15

score 1 · Accepted Answer · answered May 28 '21 at 00:18

1

You can't nest expansion operators like that. But you can just work with smaller substrings to get the result you want.

dt="${var:0:11} ${var:11:2}:${var:14:2}:${17:2}"

answered May 28 '21 at 00:18

Barmar

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score 0 · Answer 2 · answered May 31 '21 at 12:14

Thanks Barmar for your answer.

I just want to clarify that in the end, as I needed the date-time to be used for the ExifTool, I did not need to do any prior Linux variable substitution as ExifTool had a way to specify whatever date-time format is used in the file name to extract it by using the -d option. So this is what I ended up doing. Note that I didn't even have to remove the ending CX.mov character for ExifTool to get the date-time right:

exiftool -d '%Y-%m-%d $H-%M-%S' \
    '-DateTimeOriginal<${FileName}' \
    '-CreateDate<${FileName}' \
    '-MediaCreateDate<${FileName}' "${file}"

Embedded parameter substitution

2 Answers2